7x+20=6x^2

Solution for 7x+20=6x^2 equation:

7x+20=6x^2

We move all terms to the left:

7x+20-(6x^2)=0

determiningTheFunctionDomain
-6x^2+7x+20=0

a = -6; b = 7; c = +20;
Δ = b2-4ac
Δ = 72-4·(-6)·20
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-23}{2*-6}=\frac{-30}{-12}
=2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+23}{2*-6}=\frac{16}{-12}
=-1+1/3
$